3-0.3x^2-16x+500=0

Solution for 3-0.3x^2-16x+500=0 equation:

3-0.3x^2-16x+500=0

We add all the numbers together, and all the variables

-0.3x^2-16x+503=0

a = -0.3; b = -16; c = +503;
Δ = b2-4ac
Δ = -162-4·(-0.3)·503
Δ = 859.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-\sqrt{859.6}}{2*-0.3}=\frac{16-\sqrt{859.6}}{-0.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+\sqrt{859.6}}{2*-0.3}=\frac{16+\sqrt{859.6}}{-0.6}
$